Question

How do you find `h(4)` given `h(n)=n^3+6n`?

Answer 1

`h(4)=88`

Explanation:

`"to evaluate " h(4)" substitute " n=4" into " h(n)`

`h(color(red)(4))=(color(red)(4))^3+(6xxcolor(red)(4))`

`color(white)(h(4))=64+24`

`color(white)(h(4))=88`