How do you find $h (- 5)$ $h(-5)$ given $h (n) = n^{3} + 3 n^{2}$ $h(n)=n^3+3n^2$ ?

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How do you find $h (- 5)$ $h(-5)$ given $h (n) = n^{3} + 3 n^{2}$ $h(n)=n^3+3n^2$ ?

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Answer 1 · 2017-03-12T14:06:39

$h (- 5) = - 50$ $h(-5)=-50$

Explanation:

To evaluate h( -5) substitute n = - 5 into h( n)

$\Rightarrow h (- 5) = {(- 5)}^{3} + 3 {(- 5)}^{2}$ $rArrh(color(red)(-5))=(color(red)(-5))^3+3(color(red)(-5))^2$

$\times \times \times x = - 125 + (3 \times 25)$ $color(white)(xxxxxxx)=-125+(3xx25)$

$\times \times \times x = - 125 + 75$ $color(white)(xxxxxxx)=-125+75$

$\times \times \times x = - 50$ $color(white)(xxxxxxx)=-50$

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How do you find $h (- 5)$ $h(-5)$ given $h (n) = n^{3} + 3 n^{2}$ $h(n)=n^3+3n^2$ ?

1 Answer

Explanation:

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How do you find $h (- 5)$ $h(-5)$ given $h (n) = n^{3} + 3 n^{2}$ $h(n)=n^3+3n^2$ ?