How do you find $h (6)$ $h(6)$ given $h (t) = | t + 2 | + 3$ $h(t)=abs(t+2)+3$ ?

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Answer 1 · 2016-10-15T00:33:14

$h (6) = 11$ $h(6) = 11$

$h (6)$ $h(6)$ tells you to replace $t$ $t$ with $6$ $6$ and simplify the expression.

$h (6) = | 6 + 2 | + 3$ $h(6) = |6 + 2| + 3$
$h (6) = | 8 | + 3$ $h(6) = |8| + 3$
$h (6) = 8 + 3$ $h(6) = 8 + 3$
$h (6) = 11$ $h(6) = 11$

How do you find h(6)h(6) given h(t)=|t+2|+3h(t)=abs(t+2)+3?