How do you find $(h - g) (n)$ $(h-g)(n)$ given $h (n) = 4 n + 5$ $h(n)=4n+5$ and $g (n) = 3 n + 4$ $g(n)=3n+4$ ?

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Answer 1 · 2017-07-03T04:48:23

$(h - g) (n) = n + 1$ $(h-g)(n)=n+1$

To find the new function all you have to do is apply the operation in the order that is specified. In this case, subtract the two functions:

$(h - g) (n) = h (n) - g (n)$ $(h-g)(n)=h(n)-g(n)$

$\Rightarrow (h - g) (n) = [4 n + 5] - [3 n + 4]$ $rArr(h-g)(n)=[4n+5]-[3n+4]$

$\Rightarrow (h - g) (n) = (4 n - 3 n) + (5 - 4) = n + 1$ $rArr(h-g)(n)=(4n-3n)+(5-4)=n+1$

How do you find (h-g)(n)(h−g)(n)(h-g)(n) given h(n)=4n+5h(n)=4n+5h(n)=4n+5 and g(n)=3n+4g(n)=3n+4g(n)=3n+4?