How do you find $(h - g) (t)$ $(h-g)(t)$ given $h (t) = 2 t + 1$ $h(t)=2t+1$ and $g (t) = 2 t + 2$ $g(t)=2t+2$ ?

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How do you find $(h - g) (t)$ $(h-g)(t)$ given $h (t) = 2 t + 1$ $h(t)=2t+1$ and $g (t) = 2 t + 2$ $g(t)=2t+2$ ?

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Answer 1 · 2017-05-26T13:56:39

$(h - g) (t) = - 1$ $(h-g)(t)=-1$

Explanation:

$Preamble$ $color(blue)("Preamble")$

$h (t)$ $h(t)$ is just an identifier for a particular process applied to the variable $t$ $t$

So $h (t) = 2 t + 1 and h (s) = 2 s + 1 and h (b) = 2 b + 1$ $h(t)=2t+1 and h(s)=2s+1 and h(b)=2b+1$

So $g (t) = 2 t + 2 and g (s) = 2 s + 2 and g (b) = 2 b + 2$ $g(t)=2t+2 and g(s)=2s+2 and g(b)=2b+2$
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$Answering the question$ $color(blue)("Answering the question")$

The question can also be written as: $h (t) - g (t)$ $h(t)-g(t)$

$h (t) \to 2 t + 1$ $h(t)->2t+1$
$g(t)->ul(2t+2)larr" subtract"$
$" "0t-1$

$(h-g)(t)=-1$

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How do you find $(h - g) (t)$ $(h-g)(t)$ given $h (t) = 2 t + 1$ $h(t)=2t+1$ and $g (t) = 2 t + 2$ $g(t)=2t+2$ ?

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How do you find (h-g)(t)(h−g)(t)(h-g)(t) given h(t)=2t+1h(t)=2t+1h(t)=2t+1 and g(t)=2t+2g(t)=2t+2g(t)=2t+2?

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How do you find $(h - g) (t)$ $(h-g)(t)$ given $h (t) = 2 t + 1$ $h(t)=2t+1$ and $g (t) = 2 t + 2$ $g(t)=2t+2$ ?