How do you find $h(n-3)$ given $h(n)=-n-2$ ?

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Answer 1 · 2017-03-17T02:33:56

See the entire solution process below:

To solve this function for $(n - 3)$ we must substitute $color(red)((n - 3)$ for every occurrence of $color(red)(n)$ in $h(n)$ :

$h(color(red)(n)) = -color(red)(n) - 2$ becomes:

$h(color(red)(n - 3)) = -color(red)((n - 3)) - 2$

$h(color(red)(n - 3)) = -n + 3 - 2$

$h(color(red)(n - 3)) = -n + 1$

How do you find h(n-3)h(n-3) given h(n)=-n-2h(n)=-n-2?