How do you find h(x-2) given f(x)=2x-1 and g(x)=3x and h(x)=x^2+1?
1 Answer
Mar 12, 2017
Explanation:
To evaluate h( x - 2) substitute x = x - 2 in h( x)
h(color(red)(x-2))=(color(red)(x-2))^2+1
color(white)(x-2xx)=x^2-4x+4+1
color(white)(xxxxxx)=x^2-4x+5