Question

How do you find `-i+(7-5i)-3(2-3i)`?

Answer 1

`1+3i`

Explanation:

`-i + (7-5i)-3(2-3i)`

Expand:
`-> -i + 7-5i-6+9i`

Sum real and imaginary parts:
`-> 7-6 +9i-5i-i`

`=1+3i`