How do you find $\int \frac{2 x}{x^{2} + 1} d x$ $int (2x)/(x^2+1)dx$ ?

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Answer 1 · 2015-02-04T18:16:05

The answer is: $ln (x^{2} + 1) + c$ $ln(x^2+1)+c$ .

Since the numerator is the derivative of the denominator, using this rule:

$int(f'(x))/f(x)dx=lnf(x)+c$

we have the answer.

How do you find int (2x)/(x^2+1)dx∫2xx2+1dxint (2x)/(x^2+1)dx?