How do you find k(-3t)k(−3t) given k(t)=-4t+2k(t)=−4t+2?

1 Answer
Tony B
Jan 28, 2017

k(-3t) =-12t-6k(−3t)=−12t−6

Explanation:

The purpose of the letter k within the context of k(t)k(t) is that it is an identifyer for a particular structure of equation using the variable tt

A different structure could for example be given the identifying name of g(x)g(x). Yet another structure could be given the identifying name of h(x)h(x).

Suppose h(x)=3x^2-5x+2h(x)=3x2−5x+2 then h(t)=3t^2-5t+2h(t)=3t2−5t+2
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Just for the sake of clarity set " "k(t)=s=-4t+2 k(t)=s=−4t+2

So" "k(-3t) =-3s=-3(4t+2) = -12t-6 k(−3t)=−3s=−3(4t+2)=−12t−6

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