Question

How do you find k so that the line through (k,k+1) and (2,3) will have a slope of -1?

Answer 1

I could not find `k`!

Explanation:

Consider the general relationship that gives you the slope `m` as:
`m=(Deltay)/(Deltax)=(y_2-y_1)/(x_2-x_1)` (1)
Let us use our data:
`-1=(3-(k+1))/(2-k)` and solve for `k`:
`k-2=3-k-1`
`k+k=3+2-1`
`2k=4`
so `k=4/2=2`
BUT if you try this solution into your slope (equation 1) it doesn't work.
So I think it is not possible to have a line with this slope...