How do you find #lim (1+2t^-1)/(7+t^-1-5t^-2)# as #t->0#?
1 Answer
Nov 2, 2017
The answer is
Explanation:
This is an indeterminate form
Let's perform some simplifications
graph{(1+2/x)/(7+1/x-5/x^2) [-7.02, 7.024, -3.51, 3.51]}