Question

How do you find other zeros given one zero `f(x)=x^3-8x^2+4x+48; 4`?

Answer 1

`-2 and 6`.

Explanation:

`(x-4)` is a factor of f.

Upon division by (x - 4), the other factor of f is obtained as

`x^2-4x-12=(x-6)(x+2)`.

So, the other roots are given by

`x-6=x+2=0`