How do you find other zeros given one zero $f(x)=x^3-8x^2+4x+48; 4$ ?

Question

27632 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-27T03:20:32

$-2 and 6$ .

$(x-4)$ is a factor of f.

Upon division by (x - 4), the other factor of f is obtained as

$x^2-4x-12=(x-6)(x+2)$ .

So, the other roots are given by

$x-6=x+2=0$

How do you find other zeros given one zero f(x)=x^3-8x^2+4x+48; 4f(x)=x^3-8x^2+4x+48; 4?