How do you find $p (2)$ $p(2)$ given $p (t) = - t^{3} + 4 t^{2}$ $p(t)=-t^3+4t^2$ ?

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Answer 1 · 2017-08-30T00:53:02

$p (2) = 8$ $p(2)=8$

$p (2)$ $p(2)$ is a way of saying when $t = 2$ $t=2$ , the output of the function is...

To find $p (2)$ $p(2)$ , we substitute $2$ $2$ for every $t$ $t$ in the equation $- t^{3} + 4 t^{2}$ $-t^3+4t^2$ and evaluate:

$p (2) = - {(2)}^{3} + 4 {(2)}^{2}$ $p(2)=-(2)^3+4(2)^2$

$= - (8) + 4 (4)$ $=-(8)+4(4)$

$= - 8 + 16$ $=-8+16$

$= 8$ $=8$

How do you find p(2)p(2) given p(t)=−t3+4t2p(t)=-t^3+4t^2 ?