How do you find $p (- 4 x)$ $p(-4x)$ given $p (x) = x^{2} - 5 x$ $p(x)=x^2-5x$ ?

Question

4332 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-02-07T14:08:54

See the entire solution process below:

To find $p (- 4 x)$ $p(-4x)$ we must substitute $- 4 x$ $color(red)(-4x)$ for each occurrence of $x$ $color(red)(x)$ in the function $p (x)$ $p(x)$ .

$p (x) = x^{2} - 5 x$ $p(color(red)(x)) = color(red)(x)^2 - 5color(red)(x)$ becomes:

$p (- 4 x) = {(- 4 x)}^{2} - (5 \times - 4 x)$ $p(color(red)(-4x)) = (color(red)(-4x))^2 - (5 xx color(red)(-4x))$

$p (- 4 x) = 16 x^{2} - (- 20 x)$ $p(color(red)(-4x)) = 16x^2 - (-20x)$

$p (- 4 x) = 16 x^{2} + 20 x$ $p(color(red)(-4x)) = 16x^2 + 20x$

How do you find p(−4x)p(-4x) given p(x)=x2−5xp(x)=x^2-5x?