How do you find $p (- 6)$ $p(-6)$ given $p (a) = a^{3} - 4 a$ $p(a)=a^3-4a$ ?

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Answer 1 · 2017-01-31T23:49:41

See the entire solution process below:

To find $p (- 6)$ $p(-6)$ substitute $- 6$ $color(red)(-6)$ for each occurrence of the variable $a$ $color(red)(a)$ in the function from the problem:

$p (a) = a^{3} - 4 a$ $p(color(red)(a)) = color(red)(a)^3 - 4color(red)(a)$ becomes:

$p (- 6) = {- 6}^{3} - (4 \times - 6)$ $p(color(red)(-6)) = color(red)(-6)^3 - (4 xx color(red)(-6))$

$p (- 6) = - 216 - (- 24)$ $p(color(red)(-6)) = -216 - (-24)$

$p (- 6) = - 216 + 24$ $p(color(red)(-6)) = -216 + 24$

$p (- 6) = - 192$ $p(color(red)(-6)) = -192$

How do you find p(−6)p(-6) given p(a)=a3−4ap(a)=a^3-4a?