How do you find $p (t - 2)$ $p(t-2)$ given $p (t) = 4 t - 5$ $p(t)=4t-5$ ?

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Answer 1 · 2016-08-02T12:14:59

$p (t - 2) = 4 t - 13$ $p(t-2)=4t-13$

As $p (t) = 4 t - 5$ $p(t)=4t-5$

$p (t - 2) = 4 (t - 2) - 5$ $p(t-2)=4(t-2)-5$

= $4 t - 8 - 5$ $4t-8-5$

= $4 t - 13$ $4t-13$

How do you find p(t-2)p(t−2)p(t-2) given p(t)=4t-5p(t)=4t−5p(t)=4t-5?