How do you find #S_n# for the arithmetic series given #a_n=23/10#, d=1/5, n=10?
1 Answer
Dec 17, 2016
Explanation:
Our first order of business is to find the starting term,
#t_n = a + (n - 1)d#
#23/10 = a + (10 - 1)(1/5)#
#23/10 = a + 9/5#
#23/10 - 9/5 = a#
#5/10 = a#
#a = 1/2#
The sum is given by the formula
#s_10 = 10/2(1/2 + 23/10)#
#s_10 = 5(28/10)#
#s_10 = 28/2#
#s_10 = 14#
Hopefully this helps!