How do you find slope and y-intercept of $- 5 x = 8 y$ $-5x=8y$ ?

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Answer 1 · 2016-08-19T01:09:07

Put the equation into the form y = mx + b:
Where m = the slope and b = the y intercept.

Write the equation as $8 y = - 5 x$ $8y = -5x$ This puts $y$ $y$ on the left side of the equation.

Then solve for $y$ $y$ by dividing both sides by 8.

$\frac{8}{8} \times y = - \frac{5}{8} \times x \frac{8}{8} = 1$ $8/8 xx y = -5/8 xx x" " 8/8 = 1$

y = $- \frac{5}{8} \times x$ $-5/8 xx x$

$m = - \frac{5}{8}$ $m = -5/8$ so the slope is $- \frac{5}{8}$ $- 5/8$

(Think m = mountain slope , the angle of the line)

$b = 0$ $b = 0$ so the $y$ $y$ - intercept is at $(0, 0)$ $(0,0)$

(Think b = the beginning, the place where the line starts.)

How do you find slope and y-intercept of −5x=8y-5x=8y?