How do you find slope given $2 x - 5 y = 0$ $2x-5y=0$ ?

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Answer 1 · 2016-05-12T22:20:27

$gradient \to \frac{2}{5}$ $"gradient "-> 2/5$

That is: For every 5 along the graph has gone up 2

Objective: To end up with the general equation form $y = m x + c$ $y=mx+c$
where $m$ $m$ is the gradient.

Add $5 y$ $5y$ to both sides

$2 x - 5 y + 5 y = 0 + 5 y$ $2x-5y+5y=0+5y$

But $- 5 y + 5 y = 0$ $-5y+5y=0$

$2 x + 0 = 5 y$ $2x+0=5y$

Divide both sides by 5

$\frac{2}{5} x = \frac{5}{5} y$ $2/5x=5/5y$

But $\frac{5}{5} = 1$ $5/5 = 1$

$\frac{2}{5} x = y$ $2/5x=y$

Write as $y = \frac{2}{5} x$ $" "y=2/5x$

In this case the value of $c$ $c$ in $y = m x + c \to c = 0$ $y=mx+c" "->" "c=0$

The gradient $m = \frac{2}{5}$ $m=2/5$

How do you find slope given 2x-5y=02x−5y=02x-5y=0?