How do you find slope of the line that contains (1,6) and (10, -9)?

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Answer 1 · 2018-03-18T09:54:45

Slope $= -5/3$

Recall the slope formula.

The given points are (1,6) and (10, -9)

comparing with $(x_1, y_1) and (x_2,y_2)$
$x_1=1$ $color(white)(dddddddddddddd$ $x_2=10$
$y_1=6$ $color(white)(dddddddddddddd$ $y_2=-9$

$m = (y_2 - y_1) / (x_2 - x_1)$

$m = (-9 - 6) / (10 - 1)$

$m = (-15) / (9)$

Slope= $-15/9 = -5/3$

Answer 2 · 2018-03-18T10:12:03

$m=-5/3$

$"Slope "(m) = (y_2-y_1)/(x_2-x_1)$

Here , $x_1=1$

$y_1=6$

$x_2=10$

$y_2=-9$

$=> m = (-9-6)/(10-1)$

$=> m = -15/9$

$=> m = -5/3$