How do you find slope, y intercept and x intercept in an equation -10x-5y=0?

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How do you find slope, y intercept and x intercept in an equation -10x-5y=0?

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Answer 1 · 2016-05-23T12:59:41

Slope is $- 2$ $-2$ and intercepts on $y$ $y$ axis and $x$ $x$ axis, both are $0$ $0$ .

Explanation:

To find slope, $y$ $y$ intercept and $x$ $x$ intercept in the equation, let us convert it to slope-intercept form $y = m x + c$ $y=mx+c$ , which gives $m$ $m$ as slope of the line and $c$ $c$ as $y$ $y$ intercept.

As we have $- 10 x - 5 y = 0$ $-10x-5y=0$

$- 5 y = 10 x$ $-5y=10x$ or $y = 10 \frac{x}{- 5} = - 2 x$ $y=10x/-5=-2x$ or

$y = - 2 x + 0$ $y=-2x+0$ .

Hence, slope is $- 2$ $-2$ and $y$ $y$ intercept is $0$ $0$ .

For $x$ $x$ intercept, put $y = 0$ $y=0$ in the equation which gives

$- 10 x - 5 \times 0 = 0$ $-10x-5xx0=0$ or $- 10 x = 0$ $-10x=0$ i.e. $x = 0$ $x=0$

Hence slope is $- 2$ $-2$ and intercepts on $y$ $y$ axis and $x$ $x$ axis, both are $0$ $0$ .

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How do you find slope, y intercept and x intercept in an equation -10x-5y=0?

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