How do you find slope, y intercept and x intercept in an equation y=2x+4?

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Answer 1 · 2017-05-13T14:47:10

See a solution process below:

This equation is in slope-intercept form.

The slope-intercept form of a linear equation is: $y = m x + b$ $y = color(red)(m)x + color(blue)(b)$

Where $m$ $color(red)(m)$ is the slope and $b$ $color(blue)(b)$ is the y-intercept value.

$y = 2 x + 4$ $y = color(red)(2)x + color(blue)(4)$

Therefore:

The slope is: $m = 2$ $color(red)(m = 2)$

The y-intercept is: $b = 4$ $color(blue)(b = 4)$ or $(0, 4)$ $(0, color(blue)(4))$

To find the x-intercept, substitute $0$ $0$ for $y$ $y$ and solve for $x$ $x$ :

$y = 2 x + 4$ $y = 2x + 4$ becomes:

$0 = 2 x + 4$ $0 = 2x + 4$

$0 - 4 = 2 x + 4 - 4$ $0 - color(red)(4) = 2x + 4 - color(red)(4)$

#-color(red)(4) = 2x + 0

$- 4 = 2 x$ $-color(red)(4) = 2x$

$- \frac{4}{2} = \frac{2 x}{2}$ $-color(red)(4)/color(blue)(2) = (2x)/color(blue)(2)$

$-2 = (color(blue)(cancel(color(black)(2)))x)/cancel(color(blue)(2))$

$-2 = x$

$x = -2$

The x-intercept is $x = -2$ or $(-2, 0)$