How do you find the 108th derivative of y=cos(x)y=cos(x) ?
1 Answer
Aug 21, 2014
The answer is
d/(dx)cos x=-sin xddxcosx=−sinx
d/(dx)-sin x=-cos xddx−sinx=−cosx
d/(dx)-cos x=sin xddx−cosx=sinx
d/(dx)sin x=cos xddxsinx=cosx
Rather than doing 108 derivatives, we need to calculate 108 modulus 4; this equals 0. Although remainder works for positive dividends, it's best to get used to modulus because this works for negative dividends. Modulus 4 will return either 0, 1, 2, or 3.
d/(dx)cos x=-sin xddxcosx=−sinx (mod 4=1)
d/(dx)-sin x=-cos xddx−sinx=−cosx (mod 4=2)
d/(dx)-cos x=sin xddx−cosx=sinx (mod 4=3)
d/(dx)sin x=cos xddxsinx=cosx (mod 4=0)
So, our answer is