How do you find the 108th derivative of y=cos(x)y=cos(x) ?

1 Answer
Aug 21, 2014

The answer is y^((108))=cos(x)y(108)=cos(x)

sin xsinx and cos xcosx has a 4 derivative cycle:

d/(dx)cos x=-sin xddxcosx=sinx
d/(dx)-sin x=-cos xddxsinx=cosx
d/(dx)-cos x=sin xddxcosx=sinx
d/(dx)sin x=cos xddxsinx=cosx

Rather than doing 108 derivatives, we need to calculate 108 modulus 4; this equals 0. Although remainder works for positive dividends, it's best to get used to modulus because this works for negative dividends. Modulus 4 will return either 0, 1, 2, or 3.

d/(dx)cos x=-sin xddxcosx=sinx (mod 4=1)
d/(dx)-sin x=-cos xddxsinx=cosx (mod 4=2)
d/(dx)-cos x=sin xddxcosx=sinx (mod 4=3)
d/(dx)sin x=cos xddxsinx=cosx (mod 4=0)

So, our answer is cos xcosx.