How do you find the absolute value of #-7-2i#?
1 Answer
Apr 2, 2017
Explanation:
The absolute value of a complex number is essentially its (Euclidean) distance from
#abs(x+iy) = sqrt(x^2+y^2)#
So in our example:
#abs(-7-2i) = sqrt((-7)^2+(-2)^2) = sqrt(49+4) = sqrt(53)#