How do you find the amplitude and period of a function #y = -2/4 cos (7/2)x#?
1 Answer
Feb 27, 2016
amplitude
Explanation:
The standard form of cos function is :
y = acos(bx + c )
where
#|a| "is amplitude" , period = (2pi)/b " or " 360^@/b# and c is phase shift.here
#y = -1/2cos(7/2) x #
#rArr |a| = 1/2 " and period " = (2pi)/(7/2) = (4pi)/7 #
