Question

How do you find the amplitude and period of a function `y = -tan(x - pi/2)`?

Answer 1

An explanation is given below.

Explanation:

The `Atan(B(x-C))+D` function has `color(red)"no amplitude."`
The period is given by `pi/B`

`y=-tan(x-pi/2)`
On comparing with `Atan(B(x-C))+D`
We can see `B=1`

The period is `pi/1 = pi`

The period of the given function is `pi`