How do you find the amplitude and period of #y=6sin(1/8x)#?
1 Answer
Aug 27, 2016
amplitude = 6, period
Explanation:
The standard form of the
#color(blue)"sine function"# is
#color(red)(|bar(ul(color(white)(a/a)color(black)(y=asin(bx+c)+d)color(white)(a/a)|)))# where amplitude = |a| , period
#=(2pi)/b# phase shift
#=-c/b" and vertical shift" =d# here a = 6 ,
#b=1/8# , c = 0 and d = 0
#rArr"amplitude" =|6|=6" and period"=(2pi)/(1/8)=16pi#