How do you find the amplitude, period and graph #y=sec(3theta)#?

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Answer 1 · 2018-06-20T04:31:42

As below.

#y = A sec (Bx - C) + D#

#"Given : " y = sec (3 theta)#

#A = 1, B = 3, c = D = 0#

#"Amplitude = |A| = NONE for secant function"#

#"Period " = (2pi) / |B| = (2/3) pi#

#"Phase Shift " = -C / B = 0#

#"Vertical Shift " = D = 0#

graph{sec (3x) [-10, 10, -5, 5]}