How do you find the amplitude, period and phase shift for #y=2sin(theta+45^circ)+1#?

1 Answer
Jan 6, 2017

#2,pi,-45^@#

Explanation:

The standard form of the #color(blue)"sine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude " = |a|, " period " =(2pi)/b#

#"phase shift " =-c/b" and " d =" vertical shift"#

#"here " a=2,b=1,c=45^@" and " d=+1#

#rArr"amplitude " =|2|=2," period " =(2pi)/1=2pi#

#"and phase shift " =-45^@/1=-45^@#