Question

How do you find the amplitude, period and phase shift of `y= -3 sin (2x + pi/2)`?

Answer 1

`3 , pi and pi/2`

Explanation:

The standard form of the sine wave function is

`color(red)(|bar(ul(color(white)(a/a)color(black)(y=asin(bx+c)+d)color(white)(a/a)|)))`

where |a| is the amplitude , period`=(2pi)/b`

c , represents the phase-shift and d , the vertical shift.

here amplitude = |-3| = 3 , period`=(2pi)/2=pi`

phase-shift`=pi/2`and vertical shift = 0