How do you find the amplitude, period, and shift for #y = 2sin (2x - pi) +1#?
1 Answer
Jun 1, 2016
Explanation:
The standard form of the
#color(blue)"sine wave function"# is
#color(red)(|bar(ul(color(white)(a/a)color(black)(y=asin(bx+c)+d)color(white)(a/a)|)))# where amplitude = |a| , period
# =(2pi)/b# , c is the phase shift and
d, the vertical shift.here amplitude = |2| = 2 , period
#=(2pi)/2=pi# phase shift
#=-pi" and vertical shift "=((0),(1))#
