How do you find the amplitude, period, and shift for #y= -3 sin 2 pi x#?

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Answer 1 · 2018-03-19T05:48:57

As below.

#y = A sin (Bx - C) + D#

Given : #y = -3 sin (2 pi x)#

#Amplitude = |A| = 3#

#"Period" = P = (2pi) / |B| = cancel(2pi) / cancel(2pi) = 1#

#"Phase Shift " = (-C) / B = 0 / (2pi) = 0#

#"Vertical Shift" = D = 0#

graph{-3 sin (2 pi x) [-10, 10, -5, 5]}