How do you find the amplitude, period, phase shift for #y=cos(x-pi/6)#?

1 Answer
Jim G.
Aug 4, 2017

#1,2pi,pi/6#

Explanation:

#"the standard form of the "color(blue)"cosine function"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(y=acos(bx+c)+d)color(white)(2/2)|)))#

#"where amplitude "=|a|," period "=(2pi)/b#

#"phase shift "=-c/b" vertical shift "=d#

#"here " a=1,b=1,c=-pi/6,d=0#

#rArr" amplitude "=|1|=1," period "=2pi#

#"phase shift "=-(-pi/6)=pi/6#

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