Question

How do you find the amplitude, period, phase shift for `y=sin2x`?

Answer 1

`1,pi," no phase shift"`

Explanation:

The standard form of the `color(blue)"sine function"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(y=asin(bx+c)+d)color(white)(2/2)|)))`

`"where amplitude "=|a|," period " =(2pi)/b`

`"phase shift "=-c/b" and vertical shift "=d`

`"here "a=1,b=2,c=0,d=0`

`rArr"amplitude "=|1|=1," period "=(2pi)/2=pi`

Since c = 0 there is no phase shift.