How do you find the angle $α$ $alpha$ such that the angle lies in quadrant II and $csc α = 1.244$ $cscalpha=1.244$ ?

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How do you find the angle $α$ $alpha$ such that the angle lies in quadrant II and $csc α = 1.244$ $cscalpha=1.244$ ?

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Answer 1 · 2017-01-22T01:30:55

$126^{\circ} 50$ $126^@50$

Explanation:

$csc a = \frac{1}{sin a} = 1.244$ $csc a = 1/(sin a) = 1.244$
$sin a = \frac{1}{1.244} = 0.80$ $sin a = 1/(1.244) = 0.80$
Calculator gives -->
sin a = 0.80 --> $a = 53^{\circ} 50$ $a = 53^@50$
Trig unit circle gives another angle a (arc a) , in Quadrant II, that has the same sin value (0.80) -->
$a = 180 - 53.50 = 126^{\circ} 50$ $a = 180 - 53.50 = 126^@50$

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How do you find the angle $α$ $alpha$ such that the angle lies in quadrant II and $csc α = 1.244$ $cscalpha=1.244$ ?

1 Answer

Explanation:

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How do you find the angle alphaαalpha such that the angle lies in quadrant II and cscalpha=1.244cscα=1.244cscalpha=1.244?

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Explanation:

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How do you find the angle $α$ $alpha$ such that the angle lies in quadrant II and $csc α = 1.244$ $cscalpha=1.244$ ?