Question

How do you find the angle `alpha` such that the angle lies in quadrant II and `cscalpha=1.244`?

Answer 1

`126^@50`

Explanation:

`csc a = 1/(sin a) = 1.244`
`sin a = 1/(1.244) = 0.80`
Calculator gives -->
sin a = 0.80 --> `a = 53^@50`
Trig unit circle gives another angle a (arc a) , in Quadrant II, that has the same sin value (0.80) -->
`a = 180 - 53.50 = 126^@50`