Question

How do you find the angle `alpha` such that the angle lies in quadrant III and `tanalpha=8.000`?

Answer 1

The principal value `alpha_P`, for `tan alpha> 0` is in the first quadrant. The general value `= npi + alpha_P, n = 0, +-1, +-2, +-3,`..Here, the third quadrant (n=1) value = `pi+alpha_P.= 270-^o`

Explanation:

Interestingly, 3-sd (rounded) principal value `alpha_P`, for `tan alpha=8000`, is `90.0^o`.

So, the answer is little short of `270^o`.