How do you find the angle $α$ $alpha$ such that the angle lies in quadrant IV and $csc α = - 2.572$ $cscalpha=-2.572$ ?

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How do you find the angle $α$ $alpha$ such that the angle lies in quadrant IV and $csc α = - 2.572$ $cscalpha=-2.572$ ?

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Answer 1 · 2016-12-09T04:30:02

$- 22^{\circ} 88$ $- 22^@88$

Explanation:

csc t = -2.572
$sin t = \frac{1}{csc} = - \frac{1}{2.572} = - 0.388$ $sin t = 1/(csc) = - 1/2.572 = - 0.388$
Use calculator:
sin t = - 0.388 --> arc $t = - 22^{\circ} 88$ $t = - 22^@88$

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How do you find the angle $α$ $alpha$ such that the angle lies in quadrant IV and $csc α = - 2.572$ $cscalpha=-2.572$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you find the angle αalpha such that the angle lies in quadrant IV and cscα=−2.572cscalpha=-2.572?

1 Answer

Explanation:

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Impact of this question

How do you find the angle $α$ $alpha$ such that the angle lies in quadrant IV and $csc α = - 2.572$ $cscalpha=-2.572$ ?