How do you find the $arccos (\frac{\sqrt{3}}{2})$ $Arccos (sqrt3/2)$ ?

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How do you find the $arccos (\frac{\sqrt{3}}{2})$ $Arccos (sqrt3/2)$ ?

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Answer 1 · 2017-01-22T01:41:10

$\frac{π}{3}; \frac{5 π}{3}$ $pi/3; (5pi)/3$

Explanation:

Trig table and unit circle give -->
$cos x = \frac{\sqrt{3}}{2}$ $cos x = sqrt3/2$ --> arc $x = \pm \frac{π}{3}$ $x = +- pi/3$
The arc co-terminal to $(- \frac{π}{3})$ $(-pi/3)$ is $\frac{5 π}{3}$ $(5pi)/3$ .
Answers for $(0, 2 π)$ $(0, 2pi)$ :
$\frac{π}{3}, \frac{5 π}{3}$ $pi/3, (5pi)/3$

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How do you find the $arccos (\frac{\sqrt{3}}{2})$ $Arccos (sqrt3/2)$ ?

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