Question

How do you find the area bounded by the curve `y= 3-2x-x^2` and the x axis?

Answer 1

First let define the definite integral we need:

So:
`int_(-3)^(1)(3-2x-x^2)dx=`
`=|3x-x^2-x^3/3|_(-3)^1=`
`=(3-1-1/3)-(-9-9+27/3)=`
`=5/3+9=32/3`