How do you find the area of a triangleABC, if $∠ C = 62^{\circ}$ $angleC = 62^@$ , $b = 23.9$ $b = 23.9$ , and $a = 31.6$ $a = 31.6$ ?

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How do you find the area of a triangleABC, if $∠ C = 62^{\circ}$ $angleC = 62^@$ , $b = 23.9$ $b = 23.9$ , and $a = 31.6$ $a = 31.6$ ?

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Answer 1 · 2018-04-07T04:04:44

$Area of triangle A_{t} = 333.42 sq units$ $color(brown)("Area of triangle ") color(green)(A_t = 333.42) color(purple)(" sq units"$

Explanation:

![https://www.onlinemathlearning.com/http://area-triangle.html](https://useruploads.socratic.org/JcJUmpRZTEKpufM7ExSF_area%20of%20triangle.png)

$G i v e n : a = 31.6, b = 23.9, ˆ C = 62^{\circ}$ $"Given : a = 31.6, b = 23.9, hat C = 62^@$

Applying the formula $A_{t} = (\frac{1}{2}) a b sin C, using 2 sides and the included angle$ $A_t = (1/2) a b sin C, color(brown)(" using 2 sides and the included angle"$

$A_{t} = (\frac{1}{2}) \cdot 31.6 \cdot 23.9 \cdot sin 62 = 333.42 sq units$ $A_t = (1/2) * 31.6 * 23.9 * sin 62 = 333.42 " sq units"$

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How do you find the area of a triangleABC, if $∠ C = 62^{\circ}$ $angleC = 62^@$ , $b = 23.9$ $b = 23.9$ , and $a = 31.6$ $a = 31.6$ ?

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Explanation:

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How do you find the area of a triangleABC, if ∠C=62∘angleC = 62^@, b=23.9b = 23.9 , and a=31.6a = 31.6?

1 Answer

Explanation:

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How do you find the area of a triangleABC, if $∠ C = 62^{\circ}$ $angleC = 62^@$ , $b = 23.9$ $b = 23.9$ , and $a = 31.6$ $a = 31.6$ ?