How do you find the asymptotes for [(3x^2) + 14x + 4] / [x+2]?

1 Answer
Mar 3, 2016

One vertical asymptote x+2=0 and one slanting asymptote given by y=3x.

Explanation:

To find the asymptotes of (3x^2+14x+4)/(x+2)

we first observe the denominator (x+2), which shows that the function has one vertical asymptote x+2=0.

Further, highest degree of numerator is two and that of denominator is one, and their ratio is 3x^2/x=3x.

Hence, we have a slanting asymptote given by y=3x

graph{(3x^2+14x+4)/(x+2) [-10, 10, -5, 5]}