How do you find the asymptotes for (4x)/(x-3)4xx3?

1 Answer
Mar 1, 2016

There is a horizontal asymptote: y = 4y=4

There is a vertical asymptote: x = 3x=3

Explanation:

You can rewrite the expression.

frac{4x}{x - 3} = 4 * frac{x}{x - 3}4xx3=4xx3

= 4 * frac{(x - 3) + 3}{x - 3}=4(x3)+3x3

= 4 * (frac{x - 3}{x - 3} + frac{3}{x - 3})=4(x3x3+3x3)

= 4 * (1 + frac{3}{x - 3})=4(1+3x3)

= 4 + frac{12}{x - 3}=4+12x3

From this, you can see that

lim_{x -> oo} frac{4x}{x - 3} = lim_{x -> oo} (4 + frac{12}{x - 3}) = 4

Similarly,

lim_{x -> -oo} frac{4x}{x - 3} = lim_{x -> -oo} (4 + frac{12}{x - 3}) = 4

There is a horizontal asymptote: y = 4

You can also see that x = 3 results in division by zero. When x approaches 3 from the left, the denominator will become infinisimally less than zero. So,

lim_{x -> 3^-} frac{4x}{x - 3} = -oo

Similarly,

lim_{x -> 3^+} frac{4x}{x - 3} = oo

There is a vertical asymptote: x = 3

Below is a graph for your reference.
graph{(4x)/(x - 3) [-40, 40, -20, 20]}