How do you find the asymptotes for (4x)/(x-3)4xx−3?
1 Answer
There is a horizontal asymptote:
There is a vertical asymptote:
Explanation:
You can rewrite the expression.
frac{4x}{x - 3} = 4 * frac{x}{x - 3}4xx−3=4⋅xx−3
= 4 * frac{(x - 3) + 3}{x - 3}=4⋅(x−3)+3x−3
= 4 * (frac{x - 3}{x - 3} + frac{3}{x - 3})=4⋅(x−3x−3+3x−3)
= 4 * (1 + frac{3}{x - 3})=4⋅(1+3x−3)
= 4 + frac{12}{x - 3}=4+12x−3
From this, you can see that
lim_{x -> oo} frac{4x}{x - 3} = lim_{x -> oo} (4 + frac{12}{x - 3}) = 4
Similarly,
lim_{x -> -oo} frac{4x}{x - 3} = lim_{x -> -oo} (4 + frac{12}{x - 3}) = 4
There is a horizontal asymptote:
You can also see that
lim_{x -> 3^-} frac{4x}{x - 3} = -oo
Similarly,
lim_{x -> 3^+} frac{4x}{x - 3} = oo
There is a vertical asymptote:
Below is a graph for your reference.
graph{(4x)/(x - 3) [-40, 40, -20, 20]}