How do you find the asymptotes for $f (x) = 2 \cdot 3^{x - 4}$ $f(x)=2 * 3^(x-4)$ ?

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How do you find the asymptotes for $f (x) = 2 \cdot 3^{x - 4}$ $f(x)=2 * 3^(x-4)$ ?

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Answer 1 · 2016-02-02T11:49:41

$y = 0$ $y=0$ is the asymptote

Explanation:

As $x$ $x$ is made to approach $- \infty$ $-oo$ also $y$ $y$ approach the value zero. So, the graph approaches the line $y = 0$ $y=0$ will never intersect it no matter how $x$ $x$ becomes negative.

therefore, $y = 0$ $y=0$ is the asymptote

graph{y=2*3^(x-4) [-10, 10, -5, 5]}

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How do you find the asymptotes for $f (x) = 2 \cdot 3^{x - 4}$ $f(x)=2 * 3^(x-4)$ ?

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How do you find the asymptotes for $f (x) = 2 \cdot 3^{x - 4}$ $f(x)=2 * 3^(x-4)$ ?