How do you find the asymptotes for f(x)=(4x)/(x^2-8x+16)f(x)=4xx2−8x+16?

1 Answer
Ally A.
Jun 18, 2018

HA= y= 0y=0
VA= x= +/- 4
No slant asymptote

Explanation:

factored form of x^2-8x+16x2−8x+16 is (x-4) (x+4)(x−4)(x+4) so therefor the VA are +/- 4
no slant asymptote because the degree of the numerator is not one more higher than the degree of the denominator.
Ha is 0 because the degree of x is higher on the bottom than the top.

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