How do you find the asymptotes for $f (x) = e^{- x}$ $f(x) = e^(-x)$ ?

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How do you find the asymptotes for $f (x) = e^{- x}$ $f(x) = e^(-x)$ ?

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Answer 1 · 2016-03-10T17:24:44

Hence $x \to + \infty$ $x->+oo$ , $f (x) \to 0$ $f(x)->0$ and $x \to - \infty$ $x->-oo$ is $f (x) \to + \infty$ $f(x)->+oo$ and because $e^{- x} > 0$ $e^-x>0$ the only asymptote is the horizontal axis yy'

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How do you find the asymptotes for $f (x) = e^{- x}$ $f(x) = e^(-x)$ ?

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How do you find the asymptotes for $f (x) = e^{- x}$ $f(x) = e^(-x)$ ?