How do you find the asymptotes for f(x) = sqrt(x^2+5) - xf(x)=x2+5x?

1 Answer
Feb 6, 2017

Horizontal asymptote : y = 0 larry=0 See illustrative graph.

Explanation:

f = sqrt(x^2+5)-x =( (sqrt(x^2+5)-x)( sqrt(x^2+5)+x))/ (sqrt(x^2+5)+x)f=x2+5x=(x2+5x)(x2+5+x)x2+5+x

=(x^2+5-x^2)/ (sqrt(x^2+5)-x)+5/( sqrt(x^2+5)+x)=x2+5x2x2+5x+5x2+5+x

to 00, as x to oox

So, y = 0 is the asymptote, .

graph{(sqrt(x^2+5)-x-y)y=0 [-10, 10, -5, 5]}