Question

How do you find the asymptotes for `h(x)= (x^2-4)/(x)`?

Answer 1

oblique asymptote y = x

Explanation:

The first step is to divide out.

`rArr(x^2-4)/x=(x^2/x-4/x)=x-4/x`

thus h(x) simplifies to `h(x)=x-4/x`

as `xto+-oo,4/xto0" and " h(x)tox`

`rArry=x" is the only asymptote"`
graph{(x^2-4)/x [-10, 10, -5, 5]}