How do you find the asymptotes for $ln (x - 2)$ $ln(x-2)$ ?

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Answer 1 · 2017-10-08T23:56:23

$x = 2$ $x=2$

The logarithm function (any base) is only defined for positive values, and and asymptote occurs for $x \to 0$ $x rarr 0$

Thus for ln(x-2) we have an asymptote as $x - 2 \to 0$ $x-2 rarr 0$ , ie when $x = 2$ $x=2$ .

We can confirm this graphically:

graph{ln(x-2) [-5, 15, -15, 15]}

How do you find the asymptotes for ln(x-2)ln(x−2)ln(x-2)?