How do you find the asymptotes for R(x)= (x+2)/(x^2-64)?

1 Answer
Dec 28, 2016

See explanation

Explanation:

The expression becomes undefined at the point where you have:

("some value")/0.

So we have:

color(blue)(lim_(x^2-64->0^+) =lim_(x->8^+) (x+2)/(x^2-64) ->+oo)

color(blue)(lim_(x^2-64->0^-) =lim_(x->8^-) (x+2)/(x^2-64) -> -oo)

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Now we investigate as x->+-oo

As x becomes increasingly positive or negative the less and less influence is applied by the 2 in the numerator and the -64 in the denominator.

Thus the expression tend towards x/x^2 = 1/(+-x)

And as |x| ->oo then 1/(|x|) ->0

color(blue)(lim_(x->oo^-) (x+2)/(x^2-64)->0^-)

color(blue)(lim_(x->oo^+) (x+2)/(x^2-64)->0^+)
Tony B